<Dictionary>
  <Entry>
    <ID>502</ID>
    <SortID>515</SortID>
    <Lemma>biƕe</Lemma>
    <LemmaType>1</LemmaType>
    <Inflected>false</Inflected>
    <Irregular>false</Irregular>
    <POS>12</POS>
    <Morphology>1</Morphology>
    <MorphologyUncertain>false</MorphologyUncertain>
    <WSPage>20</WSPage>
    <WSPosition>9</WSPosition>
    <WSLetter>b</WSLetter>
    <WSClass>18</WSClass>
    <WSClassImplied>false</WSClassImplied>
    <WSClassOverride>Frageadv.</WSClassOverride>
    <WSClassOverrideReason>2</WSClassOverrideReason>
    <WSReconstruction>false</WSReconstruction>
    <WSConjecture>false</WSConjecture>
    <WSUnclear>false</WSUnclear>
    <Translation>woran?</Translation>
    <Comment1>POS? Lehmann: "interrog ptc" / Ebbinghaus: "adverbielle Verbindung" / Streitberg: "Frageadv."; duƕe daarentegen wordt door de drie bronnen zonder meer als Adv. bestempeld.</Comment1>
    <Comment2>[Ebbinghaus 1981, §159.A1]: "Wie der Instr. þê [...] wird ƕe auch in adverbiellen Verbindungen mit den Dativpräpositionen bi und du (biƕê woran, duƕê warum) gebraucht [...]"</Comment2>
    <Problematic>false</Problematic>
    <Verified>true</Verified>
    <VerificationTS>2003-09-17T20:03:23+02:00</VerificationTS>
    <ARCHIVE_StatusTS>2002-06-05T03:01:48+02:00</ARCHIVE_StatusTS>
    <ARCHIVE_Morphology>39</ARCHIVE_Morphology>
    <Gomorph.Name>Indeclinable</Gomorph.Name>
    <Gomorph.Description>Indeclinable word (preposition, conjunction, ...)</Gomorph.Description>
    <LemmaTypes.Name>Normal</LemmaTypes.Name>
    <LemmaTypes.Description>Normal lemma.</LemmaTypes.Description>
    <POSTags.Name>Adverb</POSTags.Name>
    <WSClasses.Name>Adv.</WSClasses.Name>
  </Entry>
  <UnambiguousToken>
    <Tokens.ID>13732</Tokens.ID>
    <Books.ID>3</Books.ID>
    <Books.Name>Luke</Books.Name>
    <Segments.N1>1</Segments.N1>
    <Segments.N2>18</Segments.N2>
    <Manuscripts.Code>CA</Manuscripts.Code>
    <Tokens.Position>7</Tokens.Position>
    <Tokens.Type>biƕe</Tokens.Type>
  </UnambiguousToken>
</Dictionary>